Senior Software Developer Interview Questions

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Implement a method 'find' that will find the starting index (zero based) where the second list occurs as a sub-list in the first list. It should return -1 if the sub-list cannot be found. Arguments are always given, not empty. Sample Input 1 list1 = (1, 2, 3) list2 = (2, 3) Sample Output 1 1 Explanation As second list (2, 3) is sub-list in first list (1, 2, 3) at index 1 Sample Input 2 list1 = (1, 2, 3) list2 = (3, 2) Sample Output 2 -1
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Senior Java Developer

Interviewed at Atlassian

3.1
Apr 13, 2016

Implement a method 'find' that will find the starting index (zero based) where the second list occurs as a sub-list in the first list. It should return -1 if the sub-list cannot be found. Arguments are always given, not empty. Sample Input 1 list1 = (1, 2, 3) list2 = (2, 3) Sample Output 1 1 Explanation As second list (2, 3) is sub-list in first list (1, 2, 3) at index 1 Sample Input 2 list1 = (1, 2, 3) list2 = (3, 2) Sample Output 2 -1

2. /** * A tournament tree is a binary tree * where the parent is the minimum of the two children. * Given a tournament tree find the second minimum value in the tree. * A node in the tree will always have 2 or 0 children. * Also all leaves will have distinct and unique values. * 2 * / \ * 2 3 * / \ | \ * 4 2 5 3 * * In this given tree the answer is 3. */ class Node { Integer value; Node left, right; Node(Integer value, Node left, Node right) { this.value = value; this.left = left; this.right = right; } } class Solution { /** * This should return the second minimum * int value in the given tournament tree */ public static Integer secondMin(Node root) { } }
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Senior Software Engineer

Interviewed at LinkedIn

3.8
Apr 5, 2017

2. /** * A tournament tree is a binary tree * where the parent is the minimum of the two children. * Given a tournament tree find the second minimum value in the tree. * A node in the tree will always have 2 or 0 children. * Also all leaves will have distinct and unique values. * 2 * / \ * 2 3 * / \ | \ * 4 2 5 3 * * In this given tree the answer is 3. */ class Node { Integer value; Node left, right; Node(Integer value, Node left, Node right) { this.value = value; this.left = left; this.right = right; } } class Solution { /** * This should return the second minimum * int value in the given tournament tree */ public static Integer secondMin(Node root) { } }

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