Developer Database Oracle Interview Questions

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Given a string of digits, where every digit represents a letter (1->a, 2->b, 26->z). Find the number of words that we can generate from that string. For example: 123 -> abc, lc, aw. The answer: 3 456 -> def. The answer: 1
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Software Engineer Intern

Interviewed at Meta

3.5
Mar 11, 2015

Given a string of digits, where every digit represents a letter (1->a, 2->b, 26->z). Find the number of words that we can generate from that string. For example: 123 -> abc, lc, aw. The answer: 3 456 -> def. The answer: 1

The first question is two find the largest and second largest value at each level of a binary tree. You don't need to return all values, just print out instead. the second question is to return a value in an array with the probability proportional to the weight of the value within the array. For example, in an array [4,5,6], return 4 with probability 4/15, 5 with 5/15 and 6 with 6/15. You are given a function that returns a random real number between 0 and 1
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Software Engineer

Interviewed at Meta

3.5
Nov 7, 2016

The first question is two find the largest and second largest value at each level of a binary tree. You don't need to return all values, just print out instead. the second question is to return a value in an array with the probability proportional to the weight of the value within the array. For example, in an array [4,5,6], return 4 with probability 4/15, 5 with 5/15 and 6 with 6/15. You are given a function that returns a random real number between 0 and 1

Implement a method 'find' that will find the starting index (zero based) where the second list occurs as a sub-list in the first list. It should return -1 if the sub-list cannot be found. Arguments are always given, not empty. Sample Input 1 list1 = (1, 2, 3) list2 = (2, 3) Sample Output 1 1 Explanation As second list (2, 3) is sub-list in first list (1, 2, 3) at index 1 Sample Input 2 list1 = (1, 2, 3) list2 = (3, 2) Sample Output 2 -1
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Senior Java Developer

Interviewed at Atlassian

3.2
Apr 13, 2016

Implement a method 'find' that will find the starting index (zero based) where the second list occurs as a sub-list in the first list. It should return -1 if the sub-list cannot be found. Arguments are always given, not empty. Sample Input 1 list1 = (1, 2, 3) list2 = (2, 3) Sample Output 1 1 Explanation As second list (2, 3) is sub-list in first list (1, 2, 3) at index 1 Sample Input 2 list1 = (1, 2, 3) list2 = (3, 2) Sample Output 2 -1

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