/* We are working on a security system for a badged-access room in our company's building. We want to find employees who badged into our secured room unusually often. We have an unordered list of names and entry times over a single day. Access times are given as numbers up to four digits in length using 24-hour time, such as "800" or "2250". Write a function that finds anyone who badged into the room three or more times in a one-hour period. Your function should return each of the employees who fit that criteria, plus the times that they badged in during the one-hour period. If there are multiple one-hour periods where this was true for an employee, just return the earliest one for that employee. badge_times = [ [“Paul”,”1355"], ["Jennifer”,”1910”],[" Jose”,”830"], ["Chloe","1910"], ["Jose”,”1615”],[Jose,”1640”], ["Paul”,"1405"], ["Jose””855”],[“Jose”, “930”],"1"], … [ "Amos”,”601"], ["Amos”,”602”],[“Paul”,”1416”]; Expected output (in any order) Paul: 1315 1355 1405 Jose: 830 835 855 915 930 Zhang: 10 109 110 Amos: 500 503 504 */